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uhh how do i prove \[\mathcal L \{ e^{at} F(t) \} = f(s-a)?\]
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use definition of Laplace
right so i'll have \[\Large \int_0^\infty e^{at} F(t) e^{-st} dt\] right?
right
then it will become \[\huge \int_0^\infty e^{(a-s)t} F(t)dt\] then what?
or \[\large \int\limits_{0}^{\infty} F(t) e^{-(s-a)t} dt\]compare it with general form of laplace
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well it looks like \[\huge \int \limits_0^\infty F(t)e^{-st}dt\] idk what else to say//
hmm could the answer you're looking for be \[\int \limits_0^\infty F(t) e^{-st}dt = f(s)\]
yeah and just replace s in f(s) with .....
therefore \[\int \limits_0^\infty F(t) e^{-(s-a)t} dt = f(s-a)\]
nice. cant believe i didnt think of that
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