A flare is launched from a hot-air ballon and moves in a vertical . At time t seconds the height of the flare is X metres , where x=1664-40t-(2560/t) for t>=5. The flare is launched when t=5. Find the terminal speed of the flare
@experimentX PLZ HELP
what is x?
height of the flare from the ground
http://www.wolframalpha.com/input/?i=plot+1664-40t-%282560%2Ft%29+from+0+to+40 the slope is almost constant. we need to find the slope of the line.
what would be the behavior ... as x-> infinity ?
x cannot be infinity because after it reaches a maximum height it will start to fall
sorry, t-> infinity the velocity will be constant as t->inf ... the slope will be -40 ... so this is your terminal velocity.
@experimentX u got the correct answer........Can u explain how? plz.... why t approaches infinity
@experimentX r u free
@mukushla can u help...... PLZ
he used derivative, v=x'. the velocity is actually the slope of the graph
an object reaches to its terminal velocity when It's acceleration drops to 0 and the velocity stays constant. u have \[ x=1664-40t-\frac{2560}{t}\] so \[u=\frac{dx}{dt}=-40+\frac{2560}{t^2}\]now note that \(u=\)constant when \(t \rightarrow \infty\)
oh....... terminal speed means the speed when the speed is constant
yeah...
I thought terminal speed was the speed of the flare just before it touches the ground.
yep ... !!
But why do we take t approaches infinity
@experimentX
because you would get a constant speed as t->inf ... this factor (2560/t) -> 0 as t-> inf
but the flare will not be in the air for infinite time
yeah ... everything is based on approximation there isn't such thing as infinity ... just t >> 2560 means 2560/t == 0
oh..... so actually the flare will not reach its terminal speed.. practically
right? @experimentX
there is not such thing as exact in physics. Everything is an approximation.
thanx to all who helped..........
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