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HELP! Factor 6a^3-3a^2+8a-4 By Grouping.
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what can you take common in the first two terms?
6a^3 & 3a^2 ?
yes
Ok Yes!, Then What Do I Do?.
what did u get common?
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3a^5?.
nah 3a^2 6a^3-3a^2 = 3a^2(2a-1) got it?
Kind Of?.
3a^2(2a-1) = 3a^2*2a - 3a^2*1 = 6a^3-3a^2 now?
Subtract 6a^3-3a^2?.
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6a^3-3a^2+8a-4 3a^2(2a-1) + 4(2a-1) (2a-1) (3a^2 +4) == ANSWER
Hmm I Kinda Get It; THANKS!!.
cool, get it for sure lol it ll be used much in the future classes
here is a cool test to see if factoring by grouping will work when given 4 terms|dw:1344436598609:dw| is those 2 numbers are the same, then you can use factoring by grouping
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