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Mathematics 9 Online
OpenStudy (anonymous):

Megan wrote the statement shown below. If a quadrilateral is a rectangle, then its diagonals are not perpendicular. Which of these is logically equivalent to it? If a quadrilateral is not a rectangle, then its diagonals are not perpendicular. If a quadrilateral is not a rectangle, then its diagonals are perpendicular. If the diagonals of a quadrilateral are perpendicular, then it is not a rectangle. If the diagonals of a quadrilateral are not perpendicular, then it is a rectangle.

OpenStudy (anonymous):

Please help me!!!!

OpenStudy (amistre64):

the premise is false to begin with

OpenStudy (amistre64):

but its logical equivalent, nonetheless, is its contrapositive

OpenStudy (amistre64):

if p, then q ::contraPs to :: if notq, then notp

OpenStudy (anonymous):

It just confuses me so much. So is the contrapositive always right?

OpenStudy (amistre64):

the contraP is always logically equivalent, yes

OpenStudy (amistre64):

this thing says im replying, even when im not :/

OpenStudy (anonymous):

Then it's the third option, yes?

OpenStudy (anonymous):

Thanks!!!!!

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