Megan wrote the statement shown below. If a quadrilateral is a rectangle, then its diagonals are not perpendicular. Which of these is logically equivalent to it? If a quadrilateral is not a rectangle, then its diagonals are not perpendicular. If a quadrilateral is not a rectangle, then its diagonals are perpendicular. If the diagonals of a quadrilateral are perpendicular, then it is not a rectangle. If the diagonals of a quadrilateral are not perpendicular, then it is a rectangle.
Please help me!!!!
the premise is false to begin with
but its logical equivalent, nonetheless, is its contrapositive
if p, then q ::contraPs to :: if notq, then notp
It just confuses me so much. So is the contrapositive always right?
the contraP is always logically equivalent, yes
this thing says im replying, even when im not :/
Then it's the third option, yes?
Thanks!!!!!
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