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find the volume of a regular pyramid with an equilateral triangular base with side 16.8 inches and height 25.5 inches.
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would this be right? A=1/2(25.5)(67.2) =1/2(1713.6) = 856.8 in squared
formula i found is volume = (Area * Height)/3 so... ((16.8*16.8)/2 * (25.5))/3
so, i get... 1199.52 in cubed (volume is cubed, area squared)
ok so i used the wrong formula then...thanks for pointing that out :)
so i need to find the base area first right? before i can find the surface area.
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before you can find the volume, yeah
\[the volum = base area Xthe heigt ; base area = 0.5 \times \sin (6o) \times (base side)^{2}\]
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