find the volume of a regular pyramid with an equilateral triangular base with side 16.8 inches and height 25.5 inches.

Question

anonymous · Answer

would this be right?
A=1/2(25.5)(67.2)
 =1/2(1713.6)
 = 856.8 in squared

anonymous · Answer

formula i found is volume = (Area * Height)/3
so... ((16.8*16.8)/2 * (25.5))/3

anonymous · Answer

so, i get... 1199.52 in cubed (volume is cubed, area squared)

anonymous · Answer

ok so i used the wrong formula then...thanks for pointing that out :)

anonymous · Answer

so i need to find the base area first right? before i can find the surface area.

anonymous · Answer

before you can find the volume, yeah

anonymous · Answer

$$the  volum = base  area Xthe  heigt ; base area = 0.5 \times \sin (6o) \times (base side)^{2}$$