Ask your own question, for FREE!
Mathematics 18 Online
OpenStudy (anonymous):

Simplify the expression. 12P5

OpenStudy (anonymous):

OpenStudy (lgbasallote):

hint: \[nPr = \frac{n!}{(n-r)!}\] therefore \[12P5 - \frac{12!}{(12-5)!}\] does that help?

OpenStudy (anonymous):

still not getting it sorry im hard to teach

OpenStudy (lgbasallote):

okay first...what is 12 - 5?

OpenStudy (anonymous):

7

OpenStudy (lgbasallote):

so the thing i wrote becomes \[\frac{12!}{7!}\]

OpenStudy (lgbasallote):

do you know what 12! and 7! equal to?

OpenStudy (anonymous):

No. thats where i get lost

OpenStudy (lgbasallote):

do you know what the ! mean?

OpenStudy (anonymous):

no

OpenStudy (lgbasallote):

so im guessing you're not familiar with factorials huh

OpenStudy (anonymous):

Im really dumb in case you cant tell. So thats a no

OpenStudy (lgbasallote):

basically... \[n! = n \times (n-1) \times (n-2) \times \cdots \times 1\] for example \[2! = 2 \times 1\] \[3! = 3 \times 2\times 1\] \[4! = 4\times 3 \times 2 \times 1\] \[5! = 5\times 4 \times 3 \times 2 \times 1\] do you get the concept now?

OpenStudy (lgbasallote):

and nahhh i dont think you're dumb...i blame the teacher and online schools for jumping from topic to topic without teaching the fundamenetals

OpenStudy (anonymous):

OOOHH OK!!! I get it now!!!

OpenStudy (lgbasallote):

wonderful ^_^

OpenStudy (anonymous):

So then it'd be 12x11x10x9x8x7x6x5x4x3x2x1 7x6x5x4x3x2x1?

OpenStudy (lgbasallote):

yup..notice and find what you can cancel out

OpenStudy (lgbasallote):

\[\frac{12 \times 11 \times 10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1}{7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1}\] something's cancellable

OpenStudy (anonymous):

Is the answer 95040?

OpenStudy (lgbasallote):

let me check...

OpenStudy (lgbasallote):

yup congrats

OpenStudy (anonymous):

Woop!!! Im a genius!!!! Oh yah!!!! Thanks buddy!!! (:

OpenStudy (lgbasallote):

haha welcome ^_^

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!