Question

Write the equation of the line that passes through (1, 3) and (4, 4) in standard form.

answer choices:
3x – 3y = –8

x – 3y = –9

x – 3y = –8

3x + y = 9

Answer 1

find the slope using \(m=\frac{y_2-y_1}{x_2-x_1}\) with \(x_1=1,y_1=3,x_2=4,y_2=4\)

Answer 2

I need to find the equation of a line.. @satellite73

Answer 3

you need the slope first

Answer 4

that is, in order to find the equation of the line, you have to compute the slope as the first step
then use \(y-y_1=m(x-x_1)\) and only then can you put it in the form that you want
what did you get for the slope?

Answer 5

m= 1/3

Answer 6

ok got it !

Answer 7

now use \(y-y_1=m(x-x_1)\) with \(m=\frac{1}{3}, x_1=1,y_1=3\)

Answer 8

So what equation would it be?

Answer 9

Umm

Answer 10

I think its 3x – 3y = –8

Answer 11

make the replacements i wrote and you get
\[y-3=\frac{1}{3}(x-1)\]

Answer 12

Or x – 3y = –8

i'm confused between the two because idk how to solve

Answer 13

no it is not the one you wrote

Answer 14

It's not x – 3y = –8 either?
Idk what i am doing wrong.. :/

Answer 15

now take \(y-3=\frac{1}{3}(x-1)\) and multiply by 3
maybe it is the second one you wrote, but it is not the first
lets write it

Answer 16

\[y-3=\frac{1}{3}(x-1)\]
\[3y-9=x-1\]
\[x-3y=-8\] yes it is that one

Answer 17

Ohhh okay thanks... I have another question that is similar.. Could you help me with it?

Write the equation of the line that passes through (2, 5) with a slope of 3 in point-slope form.

answer choices:
y – 2 = 3(x – 5)

y + 8 = 3(x + 5)

y + 5 = 3(x + 2)

y – 5 = 3(x – 2)

Answer 18

@satellite73