Question

Assume a stop sign is a regular octagon. A side measures 12.5 in. and a radius
is 16.25 in.What is the actual area of the surface of the stop sign?

Answer 1

Area= 1/2 (8*12.5)(16.25)
Area =(50)(16.25)=812.5 sq in.

Answer 2

Do you have an option with that value?

Answer 3

Area = (1/2) X perimeter X Apotherm
Where apotherm is the distance from the center to the bisector of a side.