Question

What is the vertex of y = |x + 1| ?

answer choices:
(–1, 0)

(0, –1)

(0, 1)

(1, 0)

Answer 1

the vortex of y=|x| is at origin
when it is shifted by amount a then general form of vortex is
\[\Large y=|x-a|\]
where a is the vortex so write it as
\[\Large y=|x-(-1)|\]
can you tell me now where the vortex is

Answer 2

What is the smallest possible value of y ?
|-2 + 1| = 1
|-1 + 1| = 0
|0 + 1| = 1

Answer 3

is it (0, 1)?

Answer 4

@jkristia
@sami-21

Answer 5

if x = 0, then what is y?

Answer 6

-1? @jkristia

Answer 7

since you equation is y = |x + 1| then if x = 1, then you have y = |1 + 1| = ?

Answer 8

oops, if x = 0 then y = |0 + 1|

Answer 9

I'm so confused.... idk what the answer would be

Answer 10

i said... (0, –1)?

Answer 11

just compare with what i mentioned early .
you can see that a=-1
so vortex will be ???

Answer 12

forget about the absolute value for a moment, then equation is y = x + 1
so if x = 0, then y = 0 + 1 = 1
if x = -1, then y = -1 + 1 = 0
right?

Answer 13

So would it be (–1, 0)?

if x= -1

Answer 14

if x is -2, then the equation is y = -2 + 1 = -1, the absolute value of |-1| = 1, so
the minimum y is when x = -1
x = -2, y = 1
x = -1, y = 0
x = 0, y = 1
etc...

Answer 15

correct, (-1, 0)

Answer 16

Oh okay... thankss @jkristia