Question

Is anyone feeling generous and want to help with a long, hard Algebra 2 problem?

Answer 1

uhh is it a set of questions?

Answer 2

The pool should be a rectangular prism. Mrs. Noether wants the pool to hold between 1400 ft3 and 3200 ft3 of water and be from 6-10 feet deep. Other than those specifications, you are free to design the pool how you'd like!

The estimated cost of the pool, besides labor, will come from the pool lining material that coats the inside of the pool and the amount of water needed to fill the pool. Determine the following:
1.The dimensions for the Noether pool that fit the above specifications
2. The amount of pool liner material that will be needed to completely line the inside of the pool (sides and bottom)
3. The amount of water that will be needed to fill the pool if the water needs to be 6 inches below the top of the pool

*Please include the work involved in determining the above measurements or an explanation for how the measurements were determined.

Draft a proposal for the Noethers that includes the above information along with a drawing of their pool. You may need to create more than one drawing to correctly convey your idea.

Answer 3

nope just a huge question that I have no clue where to begin.

Answer 4

yay word problems

Answer 5

seems the @completeidiot got this

Answer 6

lol im guessing your being sarcastic @completeidiot

Answer 7

ok first, just write down all the important stuff and ignore all the useless words

so pool is a rectangular prism
1400<volume < 3200
6<depth <10

volume = L*W*depth

Answer 8

i like how you word it better lol thanks

Answer 9

so will volume=l*w*depth help me find the amount of pool liner i need?

Answer 10

you cant solve for pool liner unless you have the actual dimensions of the pool

Answer 11

ohh okay. this might sound stupid but the < and > are confusing me some

Answer 12

just think of it as , area must be between 140 and 533.333
and not less than greater than

Answer 13

okay thanks :) so first i'm gonna divide volume / depth?

Answer 14

hmm but how do i find the volume and depth?

Answer 15

oh wait i screwed up

Answer 16

lol okay np

Answer 17

ok
area will be a rectangle
area of the pool surface = Volume/ depth
since we have two ranges
6<depth<10
1400<volume<3200

divide biggest value with biggest and smallest value with smallest
233.333<area <320

Answer 18

Whatever happened to me helping you with GCF and factoring @LaurenAshley1201

Answer 19

anyways "you are free to design the pool how you'd like!" so just pick any 2 nice numbers for the length and width so that its equal to a value thats within the area, then just pick a random depth thats between 6 and 10

and voila you have your dimensions

Answer 20

i'm sorry i forgot to reply, I got side tract. but i also couldnt open your link. Could we pick it up tomoro maybe? @Hero

Answer 21

We'll see

Answer 22

once you have the dimensions, its easier if you draw a picture of this,
the pool liner would be the surface area of the entire rectangular prism minus the area of the pool surface

Answer 23

@completeidiot seriously? lol so i'll use 8 for my depth. but what am i choosing from for my length and width? 1400 ft3 and 3200 ft3 ?

Answer 24

those are volume
any 2 numbers when multiplied are between 233.33 and 320

Answer 25

so like 25 and 10

Answer 26

okay so let's do length= 10 width= 25 and depth=8 is that good?

Answer 27

the volume of that is 2000 ft^3 which is between 1400 and 3200 so yes

Answer 28

yay! :)

Answer 29

now for pool lining, you need to calculate the surface area of this prism then subtract the area of the pool face

Answer 30

so the bottom of the pool is L*W
one side would be L*D
another would be W*D
another would be L*D
and the last side would be W*D

add those all together and you get the surface area needed for pool lining

Answer 31

okay one second!

Answer 32

I got 860!

Answer 33

er i got 810
dimensions = 10x25x8

10*25+10*8*2+25*8*2

Answer 34

how did you get 10*25*8

Answer 35

no those are just the dimensions,
if you multiplied those together, you'd get volume
the surface area is the line of numbers under it

Answer 36

nvm :) i did it again and got 810

Answer 37

ok for the final part, calculate the volume of water required to fill the pool so that the pool surface is 6 in below the top of the pool

Answer 38

:0

Answer 39

so the length and width wouldnt change, the only thing changing would be the depth of water,
it needs to be 6 in or .5 ft away from the top, so just subtract that from the depth
and find the volume

Answer 40

so it's gonna be 7.5 feet as the new depth?

Answer 41

so 10*25*7.5=1,875?

Answer 42

yup

Answer 43

ft^3
units are important
especially in physics

Answer 44

so it would be volume of water = 1,875ft.^3

Answer 45

yes, now draw a picture (for youself) with water level and everything, and you're good

i hope noethers isnt your teacher and is using this question as a form of cheap labor

Answer 46

then again an 8 ft deep pool is not practical

Answer 47

back track lol. the surface are would be 810 what?
btw. thankyou SOOOOO much you have helped me so much :) no I have to make a pool for hte dog :0 lol

Answer 48

i mean now