The second differential, d^2y/dx^2 of a curve is -3x+1
(1) Determine the expression of the gradient function, if the gradient at x=0 is 4.
(11) the expression for the equation of the curve if it passes through (1,0)

Question

The second differential, d^2y/dx^2 of a curve is -3x+1
(1) Determine the expression of the gradient function, if the gradient at x=0 is 4. 
(11) the expression for the equation of the curve if it passes through (1,0)

anonymous · Answer

How do you make vertical bars in latex?

anonymous · Answer

$$\frac{d^2y}{dx^2} = -3x + 1 $$ 
The gradient of a curve is $\frac{dy}{dx}$ so integrate the second differential for the gradient

anonymous · Answer

Vertical bars..?

anonymous · Answer

and for the question $x=0$ is given; then easy to solve for $C$

anonymous · Answer

like... $$\frac{dy}{dx}|_{x=t}$$except the bar is the same size as the derivative.

anonymous · Answer

i mean at x = 0 at 4*

anonymous · Answer

Sorry i dont know herp_derp

amistre64 · Answer

you have to incase it in left right syntax

\left. stuff \right|

amistre64 · Answer

$$\left. \frac{top}{bottom} \right|_{down}^{up}$$