Simplify and write in equivalent form with positive exponents. (4x^-2)^-2 So I have my answer, but want to make sure i am on the right track.
what's your answer?
my answer is -16x^4
close...very..
\[\Large (4x^{-2})^{-2} \implies \frac{1}{(4x^{-2})^2} \implies \frac{1}{16x^{-4}} \implies \frac{x^4}{16}\]
do you get it?
what I am having trouble understanding is why we add a one in the numberator. Are we dividing?
well i cant just leave the numerator blank can i.. \[\Large \frac{}{(4x^{-2})^2}\] that looks awkward
that's why there's a 1 in the numerator
because 1 is like the identity number
ok I guess that wouldn't make sense lol.
anything you multiply by 1 is the number itself
maybe this can help you \[\huge a^{-m} = \frac{1}{a^m}\] that means if a number has a negative exponent then you put it in the denominator
ok, so I do understand that anything multiplied by one is the same number.
so what dont you understand?
no, actually when you gave me that example, it does make sense. (if I can just remember to do this myself with similar problems.) thank you
ahh. welcome ^_^
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