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what is the minimum value of the function f(x)= 2x^2-10x+5?
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are you allowed to use calculus?
yes, which ever way i will be able to get the answer.
differentiate once
then set it to 0
then solve for x. after that differentiate again to determine if its a max. or min. concave up => min. concave down => max.
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like you sub the x into the equation where you differentiated twice and determine it
this should be fun
indeed. margejean; if you have any problems with this method please respond.
could you please help me step by step?
first differentiate f(x) = 2x^2-10x+5 with respect to x to get: f'(x) = 4x-10 Do you get how I did that?
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