Question

How many arrangements of 3 digits can be formed from the digits 0 through 9?

Answer 1

729??

Answer 2

Let me check..

Answer 3

hmm doesnt sound right...

Answer 4

9*10*10 = ??

Answer 5

900

Answer 6

0 to 9 has 10 digits. you take 3 from that...so it will be \[10C3 \implies \frac{10!}{3!(10-3)!}\]
right?

Answer 7

Arrangements @lgbasallote not selection only..

Answer 8

so permutation?

Answer 9

Yes permutation..

Answer 10

9*10*10 doesnt sound like permutation...

Answer 11

720??

Answer 12

See I have simply applied the concept..

Answer 13

\[10P3 \implies \frac{10!}{(10-3)!}\]
right? @waterineyes

Answer 14

Solve that..

Answer 15

1000

Answer 16

But you cannot fill first place with 0..

Answer 17

?

Answer 18

See:
Suppose three digit number is : ABC

Here A you can fill with : 1 to 9.

B can be filled with 0 to 9

Similarly C can be filled with 0 to 9 digits:

So how may ways:

9*10*10 = 900..

Answer 19

These are the numbers with repetition..

Answer 20

but it didnt specifically say that you cant use 0 as first digit..

Answer 21

Without repetition:

9*9*8 = ??

Answer 22

If you use 0 as first digit then it will become two digit number and not three digit.

It is understood..

Answer 23

not really..no...

Answer 24

Yes I am sure..

Answer 25

Without repetition you will get three digit numbers = 576

And with repetition you will get : 900..