Question

Piston in Figure P15.11 has a diameter of 0.250 in. Piston has a diameter of 1.50 in. Determine the magnitude F of the force necessary to support the 500 lb load in the absence of friction.

Answer 1

I converted all the units


d1 = 0.00635m =0.250in
r1 = 0.00318m
d2 = 0.0381m = 1.50in
r2 = 0.019m
m2 = 226.8kg
L = 0.254m = 10in
force exerted on object due to gravity = 226.8kg(9,8) = 2222.6N

So I assume that the pressure exerted by the piston holding 226.8kg and having a 1.50in diameter, is equal to the pressure exerted by the 0.250inch platform for it to be supported
so I set
P1 = P2

then,

Knowing P = F/A

I set up the equation to solve for force needed to be exerted on the 0.250in platform to keep the 226.8kg object supported

so,

x/((0.00318)^2pi) = 2222.64/((0.0190)^(2)pi)
= 62.26N
force needed to be exerted.

www.wolframalpha.com/input/?i=x%2F((0.00318)^2pi)+%3D+2222.64%2F((0.0190)^(2)pi)

Answer 2

Im lost

Answer 3

so it is a leaver that is being used

Answer 4

can u give me the values of this :
500lb= _____kg
and 2in = ____ m
and 12in = _____m

Answer 5

I assume I would have to add the 2.00in to the 10in to get my pivot point

Answer 6

500lb = 226.8kg
2in = 0.0508m
12in = 0.3048m

Answer 7

and 0.250=_____ in
and 1.50=_____in

Answer 8

i posted that above

Answer 9

look at d2 and d1

Answer 10

Is your answer 61.8N

Answer 11

well on the smaller piston I got 62.26N force needed to support the mass

Answer 12

since you are exerting the force on a leaver the force should be significantly smaller than that

Answer 13

I'm unsure how to deal with leavers