Algebra 2 . Substitution. mutliple choice!
If you were to use the substitution method to solve the following system, choose the new equation after the expression equivalent to y from the first equation is substituted into the second equation. 2x – y = –4 5x – 6y = 12 5(–2x – 4) – 6y = 12 5(2x + 4) – 6y = 12 5x – 6(–2x – 4) = 12 5x – 6(2x + 4) = 12
can you solve \(2x-y=-4\) for \(y\)?
would you subtract 2x from both sides
yes you could do that you would get \[-y=-2x-4\] but you have one more step to get \(y\)
i meant like. 2x-y=-4 -2x -2 y=-2?
no like this 2x - y = -4 -2x -2x -y = -2x - 4
if you subtract \(2x\) from both sides you get \(-2x-4\) on the right
oh okay. so whats next
hope that is clear, you do not subtract 2x from the left and 2 from the right next step is to solve for \(y\) you have \(-y=-2x-4\) and you want \(y\) not \(-y\) so multiply both sides by \(-1\) which is the same as changing all the signs
what do you get ?
y=2x+4?
exactly!
now for the last step replace \(y\) in the equation \(5x – 6y = 12 \) by \(2x+4\) use parentheses
is that step clear? it should look exactly like on of your possible answers above
5x-6(2x+4)=12?
you got it
thankyou very much :) so it's the last one?!
yes it is the last one
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