Choose the point which is a solution to the system of inequalities: 2x + y 7 5x – 2y 8 (3, 4) (–6, 3) (–2, –5) (1, –1)
this is easier than the last one because there are no words
am i looking for x or y?
solve for \(y\) in the first equation
so should i just plug in each one and see which one works?
\[2x+y=7\] subtract \(2x\) from both sides and get \[y=-2x+7\]
yes that would work, but we might as well solve
this is like the question you asked 2 questions ago first solve for (y\) in the first equation, get \(y = -2x+7\) then substitute \(-2x+7\) for \(y\) in the second equation and solve \[2x-2(-2x+7)=8\]
y=-2x+7 where do we plug that in?
we plug that in for \(y\) in the second equation, using parentheses
\[5x-2y=8\] becomes \[5x-2(-2x+7)=8\]
okay so 10 x^2-4x=8
i think i did that wron glol
first step is to multiply everything inside the parentheses by -2 i.e. remove parentheses using distributive property
then we will combine like terms and then we will start to solve
you want to try or you want me to write the first step?
solve for the INequalities; with 4 options, plug and play would be my bet
5x*-2x= -10x^2-4x=8
i see the confusion the first term \(5x\) is not being multiplied by the rest
\[5x-2(-2x+7)=8\] \[5x+4x-14=8\]
9x-14=8 +14 +14 9x=22 /9 /9 2.4 ? :(
ok before we go further, that is correct
so good work on that part i just solved \[2x + y=7\]\[ 5x – 2y=8 \]and got just what you did so there must be a typo in your question the answer is not one of the choices listed
maybe the question has a typo somewhere in it look carefully and see if the question is correct
i know what it is. there was supposed to be a \[\ge \] between y and 7 and a \[\le \] between 2y and 8
\[2x + y\geq7\]\[5x-2u\leq 8\] do what @amistre64 said check which ones work
yeah, unless you graph it; double checking the options is the simplest route i know if
|dw:1344525002668:dw| and these things are terrible at graphing :/
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