Question

hi everyone can someone take the time to help me with identiies please

Answer 1

What is the question?

Answer 2

@waterineyes

Answer 3

?

Answer 4

\[\large \tan(\frac{\theta}{2}) = \frac{\sin(\frac{\theta}{2})}{\cos(\frac{\theta}{2})} \implies \frac{\sin(\frac{\theta}{2})}{\cos(\frac{\theta}{2})} \times \frac{2\cos(\frac{\theta}{2})}{2\cos(\frac{\theta}{2})}\]

Answer 5

\[\frac{\sin (\theta)}{2\cos^2(\frac{\theta}{2})} \implies \frac{\sin(\theta)}{1 + \cos(\theta)}\]

Answer 6

Using:

\[2\sin(\frac{\theta}{2})\cos(\frac{\theta}{2}) = \sin(2 \times \frac{\theta}{2}) \implies \sin (\theta)\]

\[2\cos^2(\frac{\theta}{2}) = 1+ \cos(\theta)\]

Answer 7

thank you so much i have a couple more problems if you have time...

Answer 8

I can try..

Answer 9

@waterineyes

Answer 10

What is the question can you explain I am not getting that..

Answer 11

the attachment?

Answer 12

What is the question number you want to solve in the attachment ??

Answer 13

first one please

Answer 14

16 a??

right??

Answer 15

no b the one before that

Answer 16

Multiply by 4 both the sides:

\[4\sin^2(x)\cos^2(x) = \sin^2(2x)\]

Answer 17

why 4

Answer 18

So:

\[\sin^2(2x) = \frac{2 - \sqrt{2}}{4} \implies \sin(2x) = \sqrt{\frac{2 - \sqrt{2}}{4}}\]

\[\sin(2x) = 0.383\]

Answer 19

Because:

you can write that as:

\[\sin(x) \cos(x) \times \sin(x) \cos(x)\]

Now to make use of formula:

you have to multiply 2 with both:

\[2 \sin(x) \cos(x) \times 2 \sin(x) \cos(x)\]

That is why 4..

Answer 20

Are you having answers with you for that part ??

Answer 21

yes i have the answers i just didnt get how to do it! oh that makes sense now! Okay i have two more if you have time!

Answer 22

what are the answers can you tell ??

Answer 23

yours was the answer

Answer 24

I thought we have to do more in that..

Answer 25

right dont we have to find solutions