A cylindrical piece of iron pipe is shown below. The wall of the pipe is 1.25 inch thick.
What is the approximate inside volume of the pipe?
88 cubic inches
49 cubic inches
142 cubic inches
154 cubic inches
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OpenStudy (anonymous):
OpenStudy (anonymous):
@Shane_B
OpenStudy (anonymous):
nice to see both of you again lool
OpenStudy (anonymous):
help? i dontderstand how to get just the insdie
OpenStudy (anonymous):
*inside
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OpenStudy (anonymous):
lol
OpenStudy (anonymous):
so, what do you do after you get the whole volume?
OpenStudy (shane_b):
<smacks forehead>
Actually, it's even simpler than that. The volume of the inner cylinder will just be (6-2.5)/2, height = 16in) which can be plugged in the normal volume formula: V=pi r^2 h.
OpenStudy (shane_b):
All I'm doing there is subtracting the wall thickness (1.25*2=2.5) from the diameter...cutting it in half to get the new radius...and then just applying the cylinder volume formula.
OpenStudy (anonymous):
so, im confused lol
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OpenStudy (anonymous):
would the answer be 28?
OpenStudy (shane_b):
I don't want you to be confused. First, do you see where the inner radius will be \[\frac{6-2.5}{2}\]?
OpenStudy (anonymous):
do you have the answer
OpenStudy (anonymous):
yeah
OpenStudy (anonymous):
yeah to *Shane_B
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OpenStudy (anonymous):
cooool
OpenStudy (anonymous):
that would be 7.5
OpenStudy (shane_b):
Ok that leaves you with a radius of 1.75in. And you know the height of the cylinder is 16in so:\[V_{cyl}=\pi (1.75)^2(16)=?\]
OpenStudy (anonymous):
153.86
OpenStudy (shane_b):
Close enough...I used a longer version of pi
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