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Mathematics 4 Online
OpenStudy (anonymous):

A cylindrical piece of iron pipe is shown below. The wall of the pipe is 1.25 inch thick. What is the approximate inside volume of the pipe? 88 cubic inches 49 cubic inches 142 cubic inches 154 cubic inches

OpenStudy (anonymous):

OpenStudy (anonymous):

@Shane_B

OpenStudy (anonymous):

nice to see both of you again lool

OpenStudy (anonymous):

help? i dontderstand how to get just the insdie

OpenStudy (anonymous):

*inside

OpenStudy (anonymous):

lol

OpenStudy (anonymous):

so, what do you do after you get the whole volume?

OpenStudy (shane_b):

<smacks forehead> Actually, it's even simpler than that. The volume of the inner cylinder will just be (6-2.5)/2, height = 16in) which can be plugged in the normal volume formula: V=pi r^2 h.

OpenStudy (shane_b):

All I'm doing there is subtracting the wall thickness (1.25*2=2.5) from the diameter...cutting it in half to get the new radius...and then just applying the cylinder volume formula.

OpenStudy (anonymous):

so, im confused lol

OpenStudy (anonymous):

would the answer be 28?

OpenStudy (shane_b):

I don't want you to be confused. First, do you see where the inner radius will be \[\frac{6-2.5}{2}\]?

OpenStudy (anonymous):

do you have the answer

OpenStudy (anonymous):

yeah

OpenStudy (anonymous):

yeah to *Shane_B

OpenStudy (anonymous):

cooool

OpenStudy (anonymous):

that would be 7.5

OpenStudy (shane_b):

Ok that leaves you with a radius of 1.75in. And you know the height of the cylinder is 16in so:\[V_{cyl}=\pi (1.75)^2(16)=?\]

OpenStudy (anonymous):

153.86

OpenStudy (shane_b):

Close enough...I used a longer version of pi

OpenStudy (anonymous):

so 154! YAY!

OpenStudy (shane_b):

:)

OpenStudy (anonymous):

yay yaya yaya ya

OpenStudy (anonymous):

thanks

OpenStudy (shane_b):

np

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