Question

determinate k so that the polynomial can be writen q(x) * (x+2) and determinate q(x)

x^2 + 8x + k

Answer 1

\[q(x) \times (x + 2) = x^2 + 8x + k\implies q(x) = {x^2 + 8x + k \over x+2} \]

Answer 2

Is that a good hint?

Answer 3

then long devision?

Answer 4

Yeah. I am still not sure what the question means yet.

Answer 5

Is \(q(x) = x^2 + 8x + k\)?

Answer 6

yeah my english is not good

Answer 7

answers are k=12 and q(x) = x+ 6

Answer 8

\[Q(x)(x+2)=(x+a)(x+2)=x^2+8x+k\]we know the middle term comes from\[a+2=8\implies a=6\]

Answer 9

Still trying to decipher. Let's see what Turing says.

Answer 10

once you know that you can easily foil out\[(x+6)(x+2)\]and find that \(k=12\)

Answer 11

using long devision the rest is 12 and the function is x + 6 maybe thats what they want?

Answer 12

Thanks everyone !!!

Answer 13

welcome!

Answer 14

Oh, I gotcha, Turing!

Answer 15

cool, let me know if you want further clarification kalemale