Question

Is my solution correct ??

Answer 1

[2 + sqrt(-12)] * [3 + sqrt(-27)]
= [2 + sqrt(-1*12)] * [3 + sqrt(-1*27)]
= [2 + sqrt(12)*sqrt(-1)] * [3 + sqrt(27)*sqrt(-1)]
= [2 + sqrt(12)i] * [3 + sqrt(27)i]
= [2*3] + [sqrt(12)i*3] + [2*sqrt(27)i] + [sqrt(12)i*sqrt(27)i]
= [6] + [6sqrt(3)i] + [6sqrt(3)i] + [sqrt(324)*i^2]
= [6] + [12sqrt(3)i] – [18]
= 12sqrt(3)i - 12

Answer 2

you are 100% correct, nice work

Answer 3

Of course, you can also write it as -12 + 12sqrt(3)i, but that's basically the same thing (it's just in a+bi form)

Answer 4

@jim_thompson5910

Thanks for confirming that solution is correct.........☺

Answer 5

you're welcome