What is the common ratio between the successive height values of ball 1? Ball 2? Ball 3? ball 1: (1,84)(2,29)(3,15)(4,7)(5,2) ball 2: (1,84)(2,39)(3,19)(2,8)(3,4) ball 3: (1,84)(2,59)(3,43)(4,36)(5,27)
I had to do an activity where I measured the height of a ball when I dropped it from 7 feet high
please someone help me :'(
Thinking...
okay thankyou soo much!
Aha. Common ratio= h2/h1 where h1=any height. h2=height of the next bounce. Note that since this is an experiment, the common ratio will differ a little depending upon which two consecutive heights you choose.
so I just take the height divided by the next height so 84/29 = 2.9
And I do that for each of the numbers?
wait what do I write then? Which one? cause they're all different
No, it's 29/84. & yea that's what I said. They will not match exactly because of experimental errors. But they should be close nevertheless.
so 29/84=0.34 so thats my answer? or do I write all of the numbers I get?
Any one will do.
okay thankyou soo muchh!
yw. :)
can anyone answer this? If ball 1 were dropped from 2 feet higher, would the common ratio be different? Explain your answer. *I think it would right?
Because its going to fall faster and bounce higher. So that would change it right?
If ball 1 were perfect it would have to be the same. But since it isn't, you'll get slight variations...
any doubts?
nope! thankyou so much! You really helped a lot!
Bye.
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