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Mathematics 7 Online
OpenStudy (anonymous):

When I swing at a nail, I drive it all the way in with probability 1/2. With probability 1/4, I hit it half-way in, and with 1/4 probability I miss it entirely. I'm pretty sure that if I swing 4 times at a nail, I'll get it all the way in almost all the time. Let's see if I'm right. How many sequences of 4 swings could leave the nail still not knocked all the way in?

OpenStudy (anonymous):

@telliott99 I need help with this again, I got the answer wrong.

OpenStudy (anonymous):

Show me what you have.

OpenStudy (anonymous):

We did it yesterday and got 5/256 because of..

OpenStudy (anonymous):

that's all i have

OpenStudy (anonymous):

can you teach me how to do this?

OpenStudy (anonymous):

Well, maybe I was wrong, let's see.

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

I'm not sure I see a simpler way to do this. There are 4 steps with 3 possibilities at each step. That's a lot. Each path has a probability that is the product of the individual steps..

OpenStudy (anonymous):

We thought about it the other way around, which specific steps would leave the nail still poking up.

OpenStudy (anonymous):

Like 4 misses in a row is 1/4 1/4 1/4 1/4 = 1/256 A half-hit on the first attempt is 1/256 as well, but the half-hit could be on any of the 4 steps so that's 4/256.

OpenStudy (anonymous):

Yes

OpenStudy (anonymous):

Any sequence with 2 half-hits or a whole hit is all the way down.

OpenStudy (anonymous):

So I still like our answer, I guess.

OpenStudy (anonymous):

hmm.. tricky problem

OpenStudy (anonymous):

Yes. Put it out there again, and maybe ask someone else for help. Sorry.

OpenStudy (anonymous):

@Zarkon Can you help me?

OpenStudy (anonymous):

@Zarkon Are you there?

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