Mathematics
8 Online
OpenStudy (anonymous):
Help with question?
Look at picture below...
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OpenStudy (anonymous):
OpenStudy (allank):
How do you think we should work this out?
OpenStudy (anonymous):
I'm not sure... don't you need to find the vertex first? I honestly have no idea
OpenStudy (allank):
This is the one golden rule: the point(s) where the graph crosses the x-axis, the value of y is always 0.
OpenStudy (allank):
Got an idea now?
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OpenStudy (anonymous):
So y =0?
OpenStudy (allank):
Yes
OpenStudy (allank):
Now what do you do next?
OpenStudy (allank):
Kindly respond @LifeisHouseMusic
OpenStudy (anonymous):
Don't you plug in y to the equation...
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OpenStudy (allank):
Correct. Then after plugging in y=0, what kind of equation do you get?
OpenStudy (anonymous):
I'd get 0= 2x2 − 5x + 3?
OpenStudy (allank):
True. 0=2x^2-5x+3 . This is a nice quadratic equation. Solve for x, and that will give you the x intercepts. Comfortable now?
OpenStudy (anonymous):
i got x = 1, 3/2
OpenStudy (anonymous):
@allank
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OpenStudy (anonymous):
The answer choices look different though.. so which one would i chose?
OpenStudy (allank):
Remember that the x=1 is not the x-intercept. (1,0) is the x-intercept.
OpenStudy (anonymous):
I'm confused again..
OpenStudy (anonymous):
Wait. I got it. Thank you! @allank
OpenStudy (allank):
Nice. You're welcome :)