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Mathematics 8 Online
OpenStudy (anonymous):

Help with question? Look at picture below...

OpenStudy (anonymous):

OpenStudy (allank):

How do you think we should work this out?

OpenStudy (anonymous):

I'm not sure... don't you need to find the vertex first? I honestly have no idea

OpenStudy (allank):

This is the one golden rule: the point(s) where the graph crosses the x-axis, the value of y is always 0.

OpenStudy (allank):

Got an idea now?

OpenStudy (anonymous):

So y =0?

OpenStudy (allank):

Yes

OpenStudy (allank):

Now what do you do next?

OpenStudy (allank):

Kindly respond @LifeisHouseMusic

OpenStudy (anonymous):

Don't you plug in y to the equation...

OpenStudy (allank):

Correct. Then after plugging in y=0, what kind of equation do you get?

OpenStudy (anonymous):

I'd get 0= 2x2 − 5x + 3?

OpenStudy (allank):

True. 0=2x^2-5x+3 . This is a nice quadratic equation. Solve for x, and that will give you the x intercepts. Comfortable now?

OpenStudy (anonymous):

i got x = 1, 3/2

OpenStudy (anonymous):

@allank

OpenStudy (anonymous):

The answer choices look different though.. so which one would i chose?

OpenStudy (allank):

Remember that the x=1 is not the x-intercept. (1,0) is the x-intercept.

OpenStudy (anonymous):

I'm confused again..

OpenStudy (anonymous):

Wait. I got it. Thank you! @allank

OpenStudy (allank):

Nice. You're welcome :)

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