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derterminate the number k so that the polynomial can be writen as q(x) * (x+2) and determinate q(x) x^4-4x^2-2x+k
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If x+2 is a factor, then x = -2 is a solution to x^4-4x^2-2x+k = 0 So simply plug in x = -2 and solve for k
no you use long devision
you can it you want, but this way is much easier
I know its bad but I cant solve it using that T_T
just replace x with -2 and simplify
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then solve for k
that leads to -28 wish is not correct T_T
x^4-4x^2-2x+k = 0 (-2)^4-4(-2)^2-2(-2)+k = 0 16-4(4)-2(-2)+k = 0 16-16+4+k = 0 4+k = 0 k = -4
thanks!
np
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