Can someone please help me solve y = f(x)= x-3/2x+4 im trying to find it's inverse
ok is this your question?? \[\Large y=\frac{x-3}{2x+4}\]
Yes
ok first of all replace all x with y's and all y's with x \[\Large x=\frac{y-3}{2y+4}\] is it ok with you ?
sure
now solve the above for y. can you do this ?
That's were I get confused, I'm not sure on how to eliminate the format as a fraction
sorry openstudy crashed me :( let me type again.
ok
ok can i write this as \[\Large x(2y+4)=y-3\] ?
sure, I did that. Then would I make it 2xy+4x = y-3?
yes
then divide the y out?
now can i take y to the left side and 4x to the right \[\Large 2xy-y=-3-4x\] it it ok with you ?
is*
sure
ok now taking y common from the left side \[\Large \implies (2x-1)y=-3-4x\] now ok ??
I'm sorry, I'm a bit confused
ok take common y from the following and tell me what you got \[\Large 2xy-y=-3-4x\]
it would be (2x-1)y = -3-4x
yes exactly!
I know that I should try to get all my x's on one side, so I would I divide both sides by 2x-1
well done that's true !!!!!
Do I stop there, or continue?
Just one more step !! after division by 2x-1 you get \[\Large y=\frac{-3-4x}{2x-1}\] agree?
Yes, If I continue to do so... I would get y = 3-2x?
I hope I'm not making my own math rules
I mean y = 3+2x
so now you have \[\Large y=\frac{-3-4x}{2x-1}\] just replace y with \[ f^{-1}(x)\] and it is your answer \[\Large \implies f^{-1}(x)=\frac{-3-4x}{2x-1}\]
ok, thanks. How would I graph that?
graphing is a whole different story !!!
just to give you hint take different values of x .put in the above expression. you will get corresponding values of f^(-1)(x) Plot x values on x axis and f^-1(x) values on y axis.
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