Question

Totally lost on these three....

"Suppose f(x) = -3x + 2 and g(x) = 1/2x - 1. Find each value"

17) 3g(4)
18) g(-2)/f(3)
19) f(-1)/g(5)

Answer 1

u have
\[ \large g(x)=\frac{1}{2x-1} \]
to find g(5) replace x=5 in every x to right
\[ \large g(5)=\frac{1}{2\cdot5-1}=\frac{1}{10-1}=\frac{1}{9} \]

Answer 2

does this help?

Answer 3

It's actually g(x) = 1/2 times x, minus one.
Not one over 2x-1

Answer 4

it doesn't matter. take it as an example.

do u understand the substitution?

Answer 5

if
\[ \large g(x)=\frac{1}{2}x-1 \]
then if x=7
\[ \large g(7)=\frac{1}{2}\cdot7-1=\frac{7}{2}-1=\frac{5}{2} \]

Answer 6

Yeah, I get that. The trouble is when they add the fractions in on 18 and 19. I'm just totally lost....

Answer 7

\[ \large \frac{g(-2)}{f(3)}=\frac{\frac{1}{2}(-2)-1}{-3(3)+2}= \]

Answer 8

it is quite the same. just do it separatedly