Question

If f(a) = 2^a, then log base 2 f(a) =
(a) 2
(b) f(a)
(c) a
(d) 1/2^a
(e) a^2

Answer 1

hint: \[\huge \log_x y = z \implies x^z = y\]

Answer 2

so 2^x would equal 2a

Answer 3

hmm?

Answer 4

if you plug in the value you get log base 2 2a right?

Answer 5

hmm you have \[\Large f(a) = 2^a\]correct?

Answer 6

yes

Answer 7

and this is in the form \[\Large y = x^z\]
agree?

Answer 8

yup

Answer 9

so which one is a?

Answer 10

i mean which one is x

Answer 11

in \[\Large f(a) = 2^a\]

Answer 12

oh idk i just made that the solution to the problem

Answer 13

look closely
\[\huge y = x^z\]
y is the power
x is the base
z is the exponent

so in \[\huge f(a) = 2^a\]which one is x?

Answer 14

oh it's 2

Answer 15

right. which is y?

Answer 16

a

Answer 17

f(a) ?

Answer 18

f(a) is y

so which one is z?

Answer 19

just a

Answer 20

good..so

x = 2
y= f(a)
z = a

so what is \[\huge \log_x y = z\]

Answer 21

log base 2 f(a) = a

Answer 22

right. so what's the answer to your problem?

Answer 23

(c) a

Answer 24

correct

Answer 25

thank you :)

Answer 26

welcome