Find all roots of the polynomial f(x)= x^4-3x^3+4x^2-6x+4
do you mean +4 at the far end there?
Yes! oops!
hmm okay..are you familiar with remainder theorem and rational roots theorem? or no?
No :/
then i guess you have to factor this out the hard way...you know how to do long division right?
Yes
hmm are you sure this question is right? im not getting a factored form... :/
Nope I messed up I apologize
lol =))))
There is the re-re-edited
ahh better...okay...start by dividing it by x-2 and tell me what you get
I'm reading about the factor therorem would my division look like this \[2 1 1 0 0 \div -2\]
hmm?
I'm most likely very wrong
where did you get 2110 / -2?
the factor theorem is that if x - 2 is a factor that means f(2) = 0
I'm trying to look at an example in my book, but I'm failing
here's an example.. x^2 - 2x + 1 i want to know the factors to this using factor theorem i'll try x + 1 so if f(-1) = 0 that means x + 1 is a factor f(-1) = (-1)^2 - 2(-1) + 1 f(-1) = 1 + 2 + 1 f(-1) = 3 it's not 0 so x+ 1 is not a factor. now i'll try x - 1 if x - 1 is a factor f(1) should be 0 f(1) = (1)^2 - 2(1) + 1 f(1) = 1 - 2 + 1 f(1) = 0 that means x - 1 is a factor of x^2 - 2x + 1 make sense?
Yeah
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