HELP!!! (Question below)
\[f(x) \left\{ x + 5 x < -2 \right\}\] Then f(3) We didn't have the f(3) in class, I have no idea what to do
Can anyone at all help? I've been working on math over four hours already
i think you are getting no responses because this doesn't really make sense
what is the meaning of \(x+5x<2\) ?
is it f(x)=x + 5x-2 ?
even that doesn't make much sense maybe \[f(x)=x^2+5x-2\]?
umm .. yeah may be that !
"Graph the Piecewise Function" \[f(x) = \left\{ x + 5 x < -2 \right\}\] \[\left\{ |x-2| x \ge-2 \right\} \]
ooh hold on i bet i know
\[f(x) =\left\{\begin{array}{rcc} x+5& \text{if} & x <-2 \\ |x-2| & \text{if} & x \geq -2 \end{array} \right. \]
SWEET BABY JESUS YES. MY TEACHER HAS THE ANSWER KEY ONINE
ok well the answer is \(f(3)=|3-2|=|1|=1\)
how does this work? you look at \(f(3)\) and ask the not too hard question, which catagory does 3 belong to? is \(3<-2\) or is \(3\geq -2\) since it is clear that \(3\geq -2\) is true, you use the second expression to plug 3 in to
Hmm, does it look like the key is right?
probably right but messy for example \[f(-4)\] here you would use the top expression because \(-4<-2\)
so \[f(-4)=-4+5=1\] once you know how to read these it is not that hard
SInce I really don't understand this, would you reccomend dropping Advanced Algebra Honors as a freshman and go back to Algebra 1?
no this is really just a matter of reading comprehension it is not that bad once you understand how to read it
once again, what does this mean really? \[f(x) =\left\{\begin{array}{rcc} x+5& \text{if} & x <-2 \\ |x-2| & \text{if} & x \geq -2 \end{array} \right.\]
I think I can read it, it's just knowing what to do with it....
I don't get what it means, she teaches 3 lessons a day, so I really don't remember
it mean IF your input is less than -2, use the top expression \(x+5\) i.e. add 5 to the number and IF your input is greater than -2 use the bottom expression, i.e. subtract 2 and take the absolute value of the result
so for example what is \(f(5)\) ? well since 5 is bigger than -2 we use the bottom formula, subtract 2 and take the absolute value and \(|5-2|=|3|=3\)
whereas \(f(-3)\) we would use the top expression because -3 is less than -2 so \(f(-3)=-3+5=2\)
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