Ask your own question, for FREE!
Mathematics 13 Online
OpenStudy (anonymous):

HELP!!! (Question below)

OpenStudy (anonymous):

\[f(x) \left\{ x + 5 x < -2 \right\}\] Then f(3) We didn't have the f(3) in class, I have no idea what to do

OpenStudy (anonymous):

Can anyone at all help? I've been working on math over four hours already

OpenStudy (anonymous):

i think you are getting no responses because this doesn't really make sense

OpenStudy (anonymous):

what is the meaning of \(x+5x<2\) ?

OpenStudy (anonymous):

is it f(x)=x + 5x-2 ?

OpenStudy (anonymous):

even that doesn't make much sense maybe \[f(x)=x^2+5x-2\]?

OpenStudy (anonymous):

umm .. yeah may be that !

OpenStudy (anonymous):

"Graph the Piecewise Function" \[f(x) = \left\{ x + 5 x < -2 \right\}\] \[\left\{ |x-2| x \ge-2 \right\} \]

OpenStudy (anonymous):

ooh hold on i bet i know

OpenStudy (anonymous):

\[f(x) =\left\{\begin{array}{rcc} x+5& \text{if} & x <-2 \\ |x-2| & \text{if} & x \geq -2 \end{array} \right. \]

OpenStudy (anonymous):

SWEET BABY JESUS YES. MY TEACHER HAS THE ANSWER KEY ONINE

OpenStudy (anonymous):

ok well the answer is \(f(3)=|3-2|=|1|=1\)

OpenStudy (anonymous):

how does this work? you look at \(f(3)\) and ask the not too hard question, which catagory does 3 belong to? is \(3<-2\) or is \(3\geq -2\) since it is clear that \(3\geq -2\) is true, you use the second expression to plug 3 in to

OpenStudy (anonymous):

Hmm, does it look like the key is right?

OpenStudy (anonymous):

probably right but messy for example \[f(-4)\] here you would use the top expression because \(-4<-2\)

OpenStudy (anonymous):

so \[f(-4)=-4+5=1\] once you know how to read these it is not that hard

OpenStudy (anonymous):

SInce I really don't understand this, would you reccomend dropping Advanced Algebra Honors as a freshman and go back to Algebra 1?

OpenStudy (anonymous):

no this is really just a matter of reading comprehension it is not that bad once you understand how to read it

OpenStudy (anonymous):

once again, what does this mean really? \[f(x) =\left\{\begin{array}{rcc} x+5& \text{if} & x <-2 \\ |x-2| & \text{if} & x \geq -2 \end{array} \right.\]

OpenStudy (anonymous):

I think I can read it, it's just knowing what to do with it....

OpenStudy (anonymous):

I don't get what it means, she teaches 3 lessons a day, so I really don't remember

OpenStudy (anonymous):

it mean IF your input is less than -2, use the top expression \(x+5\) i.e. add 5 to the number and IF your input is greater than -2 use the bottom expression, i.e. subtract 2 and take the absolute value of the result

OpenStudy (anonymous):

so for example what is \(f(5)\) ? well since 5 is bigger than -2 we use the bottom formula, subtract 2 and take the absolute value and \(|5-2|=|3|=3\)

OpenStudy (anonymous):

whereas \(f(-3)\) we would use the top expression because -3 is less than -2 so \(f(-3)=-3+5=2\)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!