Question

What is the equation in standard form of the line which passes through (–2, –3) and has a slope of 1/2?

Answer 1

just substitute these values into point slope equations and then solve for standard form

Answer 2

Equation is given by:

\[y - y_1 = m(x-x_1)\]

Answer 3

Here: \((x_1, y_1) = (-2, -3)\) and m = 1/2

Just plug in and solve..

Answer 4

y + 3 = 1/2(x + 3)

Answer 5

y + 3 = 1/2x + 3/2

Answer 6

y = 1/2x + 9/2

Answer 7

how do i put that in standard form?

Answer 8

x1 is -2 here..

Answer 9

oh i see where i messed up!

Answer 10

\[y + 3 = \frac{1}{2}(x+2)\]


Now here multiply by 2 both the sides and tell me what did you get??

Answer 11

2y + 6 = x + 1

Answer 12

There is no need to go fast..

Do it slowly..

Is your RHS right ??

Answer 13

rhs?

Answer 14

Right hand side..

Answer 15

i think so.

Answer 16

How did you get x + 1 ??

Answer 17

oh it's x + 2

Answer 18

Standard form says that x and y should be on one side and constants on other side..

can you do that ??

Answer 19

\(2y + 6 = x + 2\)

Subtract 2y both the sides here..

Answer 20

6= -2y + x + 2

Answer 21

4 = -2y + x

Answer 22

Yes..

Now subtract 2 both the sides..

Answer 23

Now rearrange it to look better..

Answer 24

-2y + x = 4

Answer 25

i mean x – 2y = 4

Answer 26

Well Done..

Answer 27

thanks dog

Answer 28

Welcome..