Ask your own question, for FREE!
Mathematics 8 Online
OpenStudy (anonymous):

Find the missing probability in the table below. X 1 2 3 4 P(X) 0.40 0.20 0.20 ?

jimthompson5910 (jim_thompson5910):

All probabilities must add to 1 in a probability distribution

jimthompson5910 (jim_thompson5910):

So if y is the missing probability, then 0.4+0.2+0.2+y = 1

OpenStudy (anonymous):

I don't understand..

jimthompson5910 (jim_thompson5910):

add up 0.4, 0.2, and 0.2

OpenStudy (anonymous):

0.8?

jimthompson5910 (jim_thompson5910):

so there's an 80% chance that X is either 1, 2, or 3

jimthompson5910 (jim_thompson5910):

what's left over?

OpenStudy (anonymous):

20%? I think

jimthompson5910 (jim_thompson5910):

yes, there's a 20% chance of X = 4 since that's the only thing left

jimthompson5910 (jim_thompson5910):

so the missing probability is 0.2

OpenStudy (anonymous):

0.2! Got it thanks ! (:

OpenStudy (anonymous):

Can i bother you with another question?

jimthompson5910 (jim_thompson5910):

You can't have anything greater than 20% since you can't go over 100% and you can't have anything under 20% because if you fall short of 100%, then that suggests there is another possibility....when there clearly isn't so it has to be 20%

jimthompson5910 (jim_thompson5910):

sure go for it

OpenStudy (anonymous):

Given the table of M&M® distributions below, find P(not orange), the probability of selecting anything but a orange M&M at random from a large bag. Red Orange Yellow Green Blue Brown 0.13 0.20 ? 0.16 0.24 0.13

jimthompson5910 (jim_thompson5910):

those are all the possibilities and you can't choose anything else eg: you have a 13% chance of choosing Red. You have a 24% chance of choosing blue

jimthompson5910 (jim_thompson5910):

so add up all the given probabilities

OpenStudy (anonymous):

OKay hold onn

OpenStudy (anonymous):

0.86

OpenStudy (anonymous):

So i would subtract that from .1?

jimthompson5910 (jim_thompson5910):

so the missing probability must be what

jimthompson5910 (jim_thompson5910):

from 1 not 0.1

OpenStudy (anonymous):

Is .14 the answer?

jimthompson5910 (jim_thompson5910):

no, but it helps get you there

OpenStudy (anonymous):

Shoot.

jimthompson5910 (jim_thompson5910):

they want to know the probability of choosing anything but orange

jimthompson5910 (jim_thompson5910):

so add up all the probabilities that correspond to anything but orange

jimthompson5910 (jim_thompson5910):

so add the probabilities for red, yellow, green, blue, brown

OpenStudy (anonymous):

Okay i got 0.8

OpenStudy (anonymous):

Which is 80%

jimthompson5910 (jim_thompson5910):

good, so the answer is 0.8

OpenStudy (anonymous):

A thousand times thank you!

jimthompson5910 (jim_thompson5910):

which corresponds to an 80% chance of selecting something that isn't orange

jimthompson5910 (jim_thompson5910):

yw

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!