Question

Can't figure out this one problem in my Algebra 1 prep book, and I really want to figure out how to do it, and the the answer. Kinda New To This Site, So Idk how to enter in equations, so I took a screen shot of using paint :) Please Help Me, The Problem is in the comments!

Answer 1

Do you know how to find F(2) ?

Answer 2

Thats where I'm getting confused :(

Answer 3

Start with

\[\Large F(x) = \frac{2x+3}{x^3 - 5}\]

and replace EVERY copy of 'x' with '2' to get

\[\Large F(2) = \frac{2(2)+3}{(2)^3 - 5}\]

Answer 4

Then evaluate and simplify (keep it a fraction)

Answer 5

Okay, but what also confused me was that it looked like two different problems...The
-2/(f)2 and then the F(x)=2x+3/x^3-5

Answer 6

They basically want you to find F(2), which is some unknown number at this point

Then you would replace F(2) in -2/F(2) and simplify

Answer 7

They're the same problem because they're talking about the same function F(x)

Answer 8

okay so, I would just have to the equation you gave me in the previous part of the comments, and where ever I see x, replace it with 2?

Answer 9

yes and simplify

Answer 10

what do you get when you do that

Answer 11

7/3?

Answer 12

good, so

\[\Large \frac{-2}{F(2)}\]

turns into

\[\Large \frac{-2}{\frac{7}{3}}\]

now simplify this

Answer 13

So would I have to do 7 divided by 3 and then what ever the answer is, divide -2 by it?

Answer 14

no, they want you to keep everything a fraction

Answer 15

how would i but that in a calculator??

Answer 16

\[\Large \frac{-2}{\frac{7}{3}}\]


\[\Large \frac{\frac{-2}{1}}{\frac{7}{3}}\]


\[\Large \left(\frac{-2}{1}\right) \div \left(\frac{7}{3}\right)\]


\[\Large \left(\frac{-2}{1}\right) \times \left(\frac{3}{7}\right)\]

Keep going and multiply and reduce if possible

Answer 17

Ohhhhhh Okay, Let Me Try

Answer 18

ok

Answer 19

-(6/7)

Answer 20

good, you can type it in as -6/7

Answer 21

Yay! Omg, Thank you soo Much! I get it now :)

Answer 22

you're welcome, I'm glad you do