Question

which of the following possible base values of k is not consistent if y=f(x) is continuous, monotonic, and concave down for all values of x?

a. 0
b. -2
c. 0.5
d. 6
e. 1

Answer 1

0, because there would not able a change in y value

Answer 2

can you explain further? sorry i'm so confused

Answer 3

if the function is concave down, it means that f''(x)<0.

Answer 4

by the way, what kind of funciton is this? exponential?

Answer 5

it isn't specified

Answer 6

If your teacher doesn't put in the effort to write good questions, then don't put in the effort to answer them.

Answer 7

actually, I think it's -2, because if we assume it's an exponential funcion, y=-2^x is only one that's concave down

Answer 8

what do you interpret base values of k to mean

Answer 9

what do you mean K to mean?

Answer 10

@lgbasallote @TuringTest @jim_thompson5910 , I need some help here

Answer 11

this question is too vague :/

Answer 12

If y = f(x) is continuous, monotonic and concave down, this means that f(x) is always decreasing over the interval (-infinity, infinity)

Now if f(x) = k*g(x), then the above is only true if k is nonzero (g(x) is also continuous, monotonic and concave down). This my guess as to what/where k is

if k were zero, then f(x) = 0, which would mean that it wouldn't be concave down anymore

Answer 13

so it would be at 0 because that's where it would no longer be concave down

Answer 14

that's my guess anyway, yes

Answer 15

thanks so much for your help but it was -2 :(

Answer 16

hmm then I'm thinking of something completely different

Answer 17

oh, if you had f(x) = k^x or something like that and k was negative, then it wouldn't be continuous for all real values of x. So that's why k = -2 doesn't work

Answer 18

but of course, that's all based on the assumption that f(x) = k^x or something similar to it