A chemical manufacturer wishes to obtain 700L of a 24% acid solution by mixing a 40% solution with a 15% solution. How many litres of each solution should be used?

Question

anonymous · Answer

Let x be the volume of 40% acid to be mixed.
So, 700-x is the volume of 15% acid.
0.40*(x) + 0.15*(700-x) = 0.24*(700)
Solving for x,the answer is 252 L.
So, volume of 40% acid needed = 252 L and volume of 15% acid needed = 448 L.

anonymous · Answer

YES I GOT THE RIGHT ABSWER THEN!

anonymous · Answer

Congratulations genuine.

anonymous · Answer

Thank you so much @kartiksriramk

anonymous · Answer

You're welcome.