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OpenStudy (anonymous):
A chemical manufacturer wishes to obtain 700L of a 24% acid solution by mixing a 40% solution with a 15% solution. How many litres of each solution should be used?
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OpenStudy (anonymous):
Let x be the volume of 40% acid to be mixed. So, 700-x is the volume of 15% acid. 0.40*(x) + 0.15*(700-x) = 0.24*(700) Solving for x,the answer is 252 L. So, volume of 40% acid needed = 252 L and volume of 15% acid needed = 448 L.
OpenStudy (anonymous):
YES I GOT THE RIGHT ABSWER THEN!
OpenStudy (anonymous):
Congratulations genuine.
OpenStudy (anonymous):
Thank you so much @kartiksriramk
OpenStudy (anonymous):
You're welcome.
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