Question

Assuming x ≠ 0 and y ≠ 0, what is the quotient of 8x^9y^3 +2x^6 y^2+8x^3y/2x^3y

Answer 1

Long division!

Answer 2

divide term by term

Answer 3

wat did u do @jiteshmeghwal9

Answer 4

\[\frac{8x^9y^3}{2x^3y}=4x^{9-3}y^{3-1}=4x^6y^2\] for exampole
then move on to the next one and the next one

Answer 5

sorry ! i think that x=0 & y=0

Answer 6

4x^3y^3 + x^2y^2 + 4xy??

Answer 7

second term should have \(x^3\)

Answer 8

don't you divide the exponents? thats where i get lost.

Answer 9

oh i see
you subtract the exponents not divide

Answer 10

so is 4x^6y^2 + x^3y + 4 the answer @satellite73

Answer 11

it is really cancelling
for example
\[\frac{x^6}{x^3}=\frac{x\times x\times x\times x\times x\times x}{x\times x\times x}\]
\[=\frac{\cancel{x}\cancel{x}\cancel{x}x\times x\times x}{\cancel{x}\cancel{x}\cancel{x}}=x^3\]

Answer 12

yes you got it

Answer 13

thanks