Question

The minimum value of the expression 2/(15 + 2sinx - 2sqrt3 cosx)

Answer 1

have you differentiated it

Answer 2

nop

Answer 3

diff the denominator!

Answer 4

well to find the min you have to differentiate it once; to find x; then differentiate it again to determine if its min. or max.

why not you try and differentiate it ?>

Answer 5

maximize this value
(2sinx - 2sqrt3 cosx)

Answer 6

\[\large\text{Keep it in your mind}\]
\[-\sqrt{a^2+b^2}\le a\sin x+b\cos x\le\sqrt{a^2+b^2}\]

Answer 7

wat is this!

Answer 8

as Exper said u need to maximize (2sinx - 2sqrt3 cosx) is that right?

Answer 9

this is pretty old trick ... and very useful one!!

Answer 10

yeah...

@Yahoo!

Answer 11

sin is max at 1

Answer 12

so i have to subs that value here

Answer 13

r u there guys!!

Answer 14

yes yahoo u want to maximize (2sinx - 2sqrt3 cosx) according to the formula i gave u...here \(a=2\) and \(b=-2\sqrt{3}\)