Question

Help Needed :

(2log6 + 6log2) / (4log2 + log 27 - log 9 )

Answer 1

apply laws of logs
log a + log b = log ab
log a - log b = log a/b
log a^n = n log a

Answer 2

so applying this to the numerator
2 log 6 = log 6^2 = log 36
6 log 2 = log 2^6 = log 64
log 36 + log 64 = log 36*64

Answer 3

can you try simplifying the denominator?

Answer 4

what about 4 log 2?

Answer 5

i get : log 2304 base 48 .. :/

Answer 6

this is the third law in reverse
n log a = log a^n

for 4 log 2
n = 4 and a = 2

Answer 7

Got the answer ! :D Thankkyooou :D

Answer 8

log 36*64 = log 2304 - right

Answer 9

yw

Answer 10

Ans = 2 :)