Question

How many solutions are there to the quadratic equation
4x^2 + 8x + 3 = 0?

0
1
2
none of the above

Answer 1

Do you know the discriminant formula?

Answer 2

no

Answer 3

If you have ax^2 + bx + c = 0

The discriminant formula is

D = b^2 - 4ac

Answer 4

If D < 0, then you'll have no solutions

If D = 0, then you'll have one solution

If D > 0, then you'll have two solutions

Answer 5

Does that help?

Answer 6

im confused

Answer 7

Here's a similar example

Answer 8

all quadratics have "2" solutions ....

Answer 9

maybe she should try to factorize,then she'll get it

Answer 10

Problem:

Find the discriminant of 3x^2 + 11x - 4 = 0

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Steps:

3x^2 + 11x - 4 = 0 is in the form ax^2 + bx + c = 0 where

a = 3
b = 11
c = -4

Plug all this into the discriminant formula D = b^2 - 4ac to get

D = b^2 - 4ac

D = 11^2 - 4(3)(-4)

D = 121 + 48

D = 169

Since D > 0, this means that there are 2 real solutions

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Answer:

The equation 3x^2 + 11x - 4 = 0 has two real solutions. These solutions are also distinct.

Answer 11

Keep in mind that the answer above is the answer to the example problem and not your specific problem (but they're similar)