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Mathematics 17 Online
OpenStudy (anonymous):

Using sigma notation, describe the total length of 7 pictures hung side-by-side. Then find the total length the pictures occupy along the wall if the first picture has a length of 10 inches and the length of each successive picture is 4 inches longer than the previous one. (2 points) Using complete sentences, describe the characteristics and parts of sigma notation. Please also provide a unique example. (2 points) Using complete sentences, explain how sigma notation is connected to arithmetic sequences and series. (2 points)

OpenStudy (anonymous):

start basic first on is 10 then 12,14,16,18, 20, 22 total length is therefore \[10+12+14+16+18+20+22\]

Parth (parthkohli):

"Sigma notation", but I know you are typing that. I like interfering between geniuses, y'know?

OpenStudy (anonymous):

lots of ways to write in sigma notation you could say \[\sum_{n=0}^610+2n\] for example

OpenStudy (anonymous):

I only really need the first question.

OpenStudy (anonymous):

is it asking me for 2 answers?

Parth (parthkohli):

he is giving u da ancer be pashent

OpenStudy (anonymous):

I was just asking o_o, sorry.

OpenStudy (anonymous):

or if you want to start at \(n=1\) you could write \[\sum_{n=1}^710+2(n-1)\] or even \[\sum_{n=1}^78+2n\]

OpenStudy (anonymous):

Wait, you don't know how to start? You're saying if you want to start o.o...

OpenStudy (anonymous):

at 1.

Parth (parthkohli):

I'd stick to the last one. You derive the formula to start with, by the way.

OpenStudy (anonymous):

what i meant was "what do you want the lower index of summation to be?"

OpenStudy (anonymous):

Doesn't the question tell you?

OpenStudy (anonymous):

ok all that stuff was wrong anyway because it says "4 inches" not 2 inches

Parth (parthkohli):

Well, but the question doesn't ask what *Satellite* would like the lower index to be.

OpenStudy (anonymous):

so write \[\sum_{n=1}^7 6+4n\]

OpenStudy (anonymous):

isn't it 4n-10?

OpenStudy (anonymous):

that will give you \[10+14+16+20+24+28+32\]

OpenStudy (anonymous):

I meant 4n-4

OpenStudy (anonymous):

because (n-1)(4)

OpenStudy (anonymous):

?

Parth (parthkohli):

It'd be whatever you like it to be, Daren, as long as it is correct.

OpenStudy (anonymous):

oh wait your right

OpenStudy (anonymous):

I forgot the a1

OpenStudy (anonymous):

Ok thankyou, satellite73 :)

OpenStudy (anonymous):

ParthKohli, you were no help -_-

OpenStudy (anonymous):

\[a_1=10,a_2=10+4,a_3=10+8,...\]

OpenStudy (anonymous):

I understand how to do it now :)

Parth (parthkohli):

Of course I am not a help. I am just a sidekick haha!

OpenStudy (anonymous):

Not a good sidekick <.<!

OpenStudy (anonymous):

Anyone watch internet icon?

Parth (parthkohli):

Rest must go to chat, and I be a sidekick only when Satellite is there. He's the boss. lol

OpenStudy (anonymous):

I see why ...

OpenStudy (anonymous):

I don't get what you do o.O

OpenStudy (amistre64):

different authors start at different places; n=0 or n=1 is not set in stone

Parth (parthkohli):

I just get confused what to say when Satellite is there. I'm a great help if he's not there. Haha!

OpenStudy (anonymous):

I went back to the example and there's an understood 1 <.<

OpenStudy (anonymous):

In previous examples just like it.

OpenStudy (anonymous):

and n can't equal 0 <.< Idk where you got that from.

OpenStudy (amistre64):

it tends to be easier to write it up with n=0, and just change all the ns to n-1 afterwards

Parth (parthkohli):

I like sigma notation when \(n\) starts at 1.

OpenStudy (anonymous):

No, bye.

OpenStudy (anonymous):

thanks for help openstudy!

Parth (parthkohli):

You're welcome!

OpenStudy (amistre64):

n can, and often times does = 0 :/

OpenStudy (anonymous):

Not from what I'm learning :/ I guess it's more advanced than algebra 2 or is in another lesson :/

OpenStudy (amistre64):

there is a long lasting debate as to whether or not "0" is a natural number (n) or not, the debate has never been settled so different authors write their texts according to their own preferences. http://www.wolframalpha.com/input/?i=natural+number

OpenStudy (amistre64):

spose you calculating interest on an account that pays after the first year a0 = original balance a1 = balance in year 1 a2 = balance in year 2 as such n=0 is a perfered starting point.

OpenStudy (amistre64):

calculating up sequences is also easier to start with n=0; but there is no big deal either way. if you start with n=0 and want n=1; +1 to the index and -1 from the expression and the results are the adjusted for which ever one you wish to consider

OpenStudy (amistre64):

\[\sum_{i=1}^{n}i = \frac{n(n+1)}{2};~1,3,6,10,15,...\] \[\sum_{i=0}^{n}i = \frac{(n+1)(n+2)}{2};~1,3,6,10,15,...\]

OpenStudy (anonymous):

STOP AMISTRE THIS IS COMPLETELY WRONG I ALREADY HAVE THE ANSWER T_T!

OpenStudy (amistre64):

how strange :/

OpenStudy (amistre64):

are you "yelling" becasue i have defended my position? or is this just some odd form of asking me to not reply?

OpenStudy (anonymous):

Oh, I just like caps lol xD

OpenStudy (anonymous):

the answer turns out being -60

OpenStudy (amistre64):

ok, good luck with it ;)

OpenStudy (anonymous):

oh wait 154

OpenStudy (anonymous):

lol i was looking at #4

OpenStudy (anonymous):

thanks for all the effort though :)

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