Ask your own question, for FREE!
Mathematics 14 Online
OpenStudy (anonymous):

Another change of variable ODE problem...

OpenStudy (anonymous):

Really struggling with these questions I can't see what I am doing wrong....I know I've asked similar/identical questions like this before, but this is one is not working out for me at all.

OpenStudy (anonymous):

get dz/dt by itself and then integrate

OpenStudy (anonymous):

dx/dt i mean

OpenStudy (anonymous):

once you have x you can figure out what z(t) is

OpenStudy (anonymous):

I have to get the answer in the order it asks. I hate this question its more of a puzzle more than anything.

OpenStudy (anonymous):

hold on let me try my way

OpenStudy (anonymous):

@lalaly any ideas also? You've helped me on similar questions!

OpenStudy (anonymous):

@amistre64 Any ideas also? This one is driving me insane >.<

OpenStudy (anonymous):

@TuringTest Any ideas?

OpenStudy (lalaly):

x(t)=t z(t) \[\frac{dx(t)}{dt}=z(t)+t \frac{dz(t)}{dt}\]plugging it in the equaion \[t^2z(z+tz')=2t^3 e^t+te^t(zt)^2+z^2t^2\]\[t^2z^2+t^3zz'=2t^3e^t+t^3z^2e^t+z^2t^2\]\[t^3zz'=2t^3e^t+t^3z^2e^t+z^2t^2-t^2z^2\]\[t^3zz'=2t^3e^t+t^3z^2e^t\]divide by t^3 \[zz'=2e^t+z^2e^t\]so\[z \frac{dz}{dt}=e^t(2+z^2)\]

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!