Prove that the diagonals of the square bisect the interior angles.

Question

anonymous · Answer

attachment

anonymous · Answer

@Hero

anonymous · Answer

@hba

anonymous · Answer

@Outkast3r09

anonymous · Answer

@Faman39

faman39 · Answer

I m sorry lana, i wish could help u with these, unfortunely i really know this

faman39 · Answer

i really dont know it

anonymous · Answer

It's ok.. do you know some that does?

faman39 · Answer

ok, i will try to find help for u , ok :)

anonymous · Answer

:D ok

radar · Answer

If you prove Angle SPR equals angle RPQ then would you agree that the bisector did indeed bisect Angle SPQ?

anonymous · Answer

Suure lol can you explain that a lil futher please lol

radar · Answer

Bisect the angle means dividing it into two equal parts.  Now does my original post make sense?  Read it carefully.

anonymous · Answer

Lol i understood your first post lol... i meant how do you prove angle SPR = RPQ?

radar · Answer

Do you also agree segments PS = PQ by definition of a square?

radar · Answer

and furthermore,  segments ST and QT are equal as is indicated equal by the drawing.

anonymous · Answer

Yes, to the square.
And yes to the other one too

radar · Answer

Segment PT = Segment PT as it is the same, and  the segment is a side of each of the triangles (common to both).
There fore the two triangles are congruent by the SSS rule.

radar · Answer

Triangle PTS is congruent to triangle PTQ.

anonymous · Answer

Ok ok i get it now

radar · Answer

SSS is side, side, side.  Great you say you have. the two angles that make angle SPQ are corresponding angles of two congruent triangles.

radar · Answer

This applies to all the corners just different labels.

anonymous · Answer

ok thanks :)

radar · Answer

You're welcome.