Question

Rewrite the expression with positive exponents: 1/(3x-3)

Answer 1

you should use ^ to show an exponent. and put the exponent in parens
so your problem (guessing!) is
\[ \frac{1}{3x^{-3}} \]
or
\[ \frac{1}{(3x)^{-3}} \]

Answer 2

thats what ive been doing god y cant i get things :(

Answer 3

of the two, posted above which is your problem? (first or second?)

Answer 4

first

Answer 5

?

Answer 6

if it is the first, then you could write it as
1/(3x^(-3))
the first thing is write it as
(1/3) * 1/x^(-3)
\[ \frac{1}{3}\cdot \frac{1}{x^{-3}} \]

now use the rule that 1/x^(-n) = x^n (flip and change the sign of the exponent)

Answer 7

ok

Answer 8

people came up with this great idea
x*x*x*x is too hard to write, so say x^4
they decided if you want to write
\[ \frac{1}{x*x*x*x} = x^{-4} \]
use a minus 4 to show the x is in the bottom
if we flip both sides we get
\[ \frac{x*x*x*x}{1} = \frac{1}{x^{-4}} \]
of course, the left side is the same as x^4

Answer 9

\[ x^4= \frac{1}{x^{-4}} \]
can you use the same "rule" for 1/x^(-3) ?