Question

3ab/27a^3b^4

Answer 1

\[\frac{3ab}{27a^3b^4}\]
i am assuming this is your problem

Answer 2

\[\frac{3ab}{27a^3b^4}=\frac{3ab}{3ab*9a^2b^3}\]

Answer 3

yes

Answer 4

see how I factored the bottom out. Can you further simplify where I left from?

Answer 5

so it should be \[9a^{2}b^{3}\]

Answer 6

why did you bring it to the top of the fraction? I thought that part was in the bottom?

Answer 7

ok i dont get it than

Answer 8

what Ryan means is
it would look like\[\frac{1}{9a^2b^3}\]
@dino123

Answer 9

ok