Question

Radical in the denominator.. Please help?!

Answer 1

dont you just multiply numerator and denominator by \(\sqrt{9r^{13}}\)

Answer 2

I don`t really know. If you could explain it would be very helpful :D

Answer 3

you're familiar with the concept of rationalization?

Answer 4

I a little bit but if you could show me then it would be great! (:

Answer 5

okay...for example i have \[\frac{2}{\sqrt 3}\]
to rationalize it i would just multiply numerator and denominator by \(\sqrt 3\)
so i get \[\frac{2}{\sqrt 3} \times \frac{\sqrt 3}{\sqrt 3} \implies \frac{2\times \sqrt3}{\sqrt 3 \times \sqrt 3} \implies \frac{2\sqrt 3}{3}\]
get the idea?`

Answer 6

Oh! Now I do. Let me try and solve it

Answer 7

sure

Answer 8

explain why radical denominators are not mathematically "elegant"

Answer 9

\[117r ^{4}\sqrt{9r}^{13} \div {9r}^{13} \]

Answer 10

right...you can simplify it further though

Answer 11

Is it correct? S:

Answer 12

ok let me try to simplify p:

Answer 13

take your time :D

Answer 14

\[351r ^{4}\sqrt{r ^{13}} \div 9r\]

Answer 15

what happened?

Answer 16

why did the r^13 in the denominator disappear?

Answer 17

You can also simplify this one directly without rationalization. Example:\[\frac{x}{\sqrt{x^3}}=\frac{x}{x^\frac{3}{2}}=x^{1-\frac{3}{2}}=x^\frac{-1}{2}=\frac{1}{\sqrt{x}}\]Or,\[\frac{\sqrt{x}}{x}\]

Answer 18

heh you jut did rationalization =))

Answer 19

yeah, the last step.

Answer 20

Instead of doing it first...less work that way

Answer 21

Oh I meant to add the r^13

Answer 22

simplify it further

Answer 23

Idk how? ._.

Answer 24

you can still divide some things

Answer 25

The exponents confused me

Answer 26

divide 351 by 9

Answer 27

tht's a start