Question

raise the quantity in parenthesis to the indicated exponent, and simplify the resulting expression. Express with positive exponents.
(43x^-4y^4/86x^-3y^-5)^3

Answer 1

\[(43x ^{-4}y ^4 / 86x ^{-3}y ^{-5})^{3}\]

Answer 2

so i have gotten this far.....\[1x ^{-12}y ^{12}/2x ^{3}y ^{-15}\]

Answer 3

It's a bit tricky...let's hope I don't make a silly mistake typing it all out :)\[(\large \frac{43x ^{-4}y ^4}{86x ^{-3}y ^{-5}})^{3}\]\[\large (\frac{y^4y^5x^3}{2x^4})^3\]\[\large (\frac{y^9}{2x^4x})^3\]\[\large \frac{y^{27}}{8x^{15}}\]

Answer 4

ok, ty what happens to the 43/86 ?

Answer 5

It turned into 1/2....I just dropped the 1 from the top

Answer 6

oh ok, gotcha! thanks for your help! algebra is so not my forte!! lol

Answer 7

It's ok...let me check it on paper...just to be sure

Answer 8

thanks again, I am in my 2nd algebra class for college and I barely passed the first one :)

Answer 9

There is a mistake :)

Answer 10

okie doke. I'm writing it out too

Answer 11

\[(\large \frac{43x ^{-4}y ^4}{86x ^{-3}y ^{-5}})^{3}\]\[\large (\frac{y^4y^5x^3}{2x^4})^3\]\[\large (\frac{y^9}{2x})^3\]\[\large \frac{y^{27}}{8x^{3}}\]

Answer 12

I made a silly mistake with the x's....but this should be correct now.

Answer 13

thanks a bunch!

Answer 14

np :)

Answer 15

BTW: If something is unclear, just ask

Answer 16

ok

Answer 17

ok,so inthe second to last step, where did the 4 go in 2x^4 ?

Answer 18

I just divided and simplified it along the way:\[\large \frac{x^3}{x^4}=x^{-1}=\frac{1}{x}\]

Answer 19

gotcha ok ty

Answer 20

You're welcome. This all just takes a little practice then it gets easier.

Answer 21

I hope so lol my little brother is way better at this stuff and he's 7yrs younger than me :)