Question

CHALLENGE QUESTION 4

If \(x_1\), \(x_2\), \(x_3\), \(x_4\) are the roots of the equation \(x^4 - x^3 sin 2\alpha + x^2 cos 2\alpha - x cos\alpha - sin\alpha = 0\), \(\alpha\) is not equal to \(\cfrac{\pi}{6}\), then \(tan^{-1}x_1 + tan^{-1}x_2 + tan^{-1}x_3 + tan^{-1}x_4 = \)

(a) \(\alpha\) (b) \(\cfrac{\pi}{2} - \alpha\)

(c) \(-\alpha\) (d) \(\pi - \alpha\)

Answer 1

@waterineyes
@mukushla

Answer 2

@satellite73 sir can u help

Answer 3

Hi @experimentX

Answer 4

Should we find out the roots of the equation ???????? @experimentX

Answer 5

currently i have no idea.

Answer 6

may be wolfram will help in finding the roots

Answer 7

yep ... wolfram is one of the solution.