Raise the quantity in parenthesis to the indicated exponent, and simplify the resulting expression.Express answers with positive exponents.
(-36x^2y/180x^-3y^-5)^-2

This is as far as I got if it is even correct so far.... (y^6/3x^2)^-2 ????? but if this is right I'm not sure of what to do from here.

Question

Raise the quantity in parenthesis to the indicated exponent, and simplify the resulting expression.Express answers with positive exponents. 
(-36x^2y/180x^-3y^-5)^-2

This is as far as I got if it is even correct so far.... (y^6/3x^2)^-2 ????? but if this is right I'm not sure of what to do from here.

lgbasallote · Answer

uhh i dont think that's rgiht...

lgbasallote · Answer

$$-\frac{36}{180} = -\frac 15$$
$$\large \frac{x^2}{x^{-3}} = x^5$$
$$\frac{y}{y^{-5}} = y^6$$

anonymous · Answer

you know what? i had wrote on my paper that 180 divided by 36 was five, but I guess I overlooked that when I was doing my problem. thanks:)

lgbasallote · Answer

haha welcome ^)^

anonymous · Answer

I have a question about x^2/x^-3 = 5 ... are we adding them? if so how does it become positive?

anonymous · Answer

and where did the ^-2 go that was in parenthesis around the problem?

lgbasallote · Answer

$$\Large \frac{x^2}{x^{-3}} \implies x^{2  - (-3)} \implies x^{2 + 3} \implies x^5$$

lgbasallote · Answer

and the ^-2 is still there...i was just pointing out your mistakes

anonymous · Answer

oh ok thanks