horizontal asymptote of (2x-5)/(8x+2)? Please help :)

Question

lgbasallote · Answer

just equate the denominator to 0 then solve for x

so what is x when 8x + 2 =0?

anonymous · Answer

-1/4

alexwee123 · Answer

he said horizontal not vertical @lgbasallote  :DD

lgbasallote · Answer

uhh good point...

anonymous · Answer

Yeah, I know that's how you solve vertical

lgbasallote · Answer

well there's no y...how can you find the horizontal asynptote o.O

anonymous · Answer

One of the choices is "there is no horizontal asymptote" so would that be the answer? haha

alexwee123 · Answer

@MathFreak106 na it would be 2/8 or 1/4

lgbasallote · Answer

i was just saying this wasnt a function lol...you didnt show where the y is

anonymous · Answer

@alexwee123  Ok I see. You divided the coefficients because the degree is the same?

alexwee123 · Answer

yep :D

anonymous · Answer

look at the coefficients oh highest powers in numerator and denominator if they are equal then their coefficients ratio is horizontal asymptotic.

for example
y=(4x+5)/(5x+7)
the powers are same so horizontal asymptotic should be
y=4/5

anonymous · Answer

@lgbasallote haha i meant to put f(x)

alexwee123 · Answer

@MathFreak106 look at this site for more reference if you need it http://www.freemathhelp.com/finding-horizontal-asymptotes.html

anonymous · Answer

Thanks!!