Solve the differential equation (2x+7y)dx-(4x-y)dy=0 .... Thanks ! =)
use homogeneous thingies
can you show me how ? and how did you know it's homogenous ?
homogeneous thingies !
it is non Exact differential equation. you will have to find integrating factor to make it exact.
yes. thank you. but can you explain more ? how did you know it's homogenous and how can i solve it ? thanks !
you can use x=tx and y=ty if you can take out t back then it is homogeneous.
@lgbasallote help him .sorry i got a go :(
normally when everything has the same degree it is homogeneous...
andeverything here has degree of 1 so i know it is homogeneous
bye everything i mean all terms
\[(2x+7y)\text dx-(4x-y)\text dy=0\]\[2x+7y\text dx=(4x-y)\text dy\]\[\frac{2x+7y}{4x-y}=\frac{\text dy}{\text dx}\] \[\frac{\text dy}{\text dx}=\frac{2x+7y}{4x-y}=\frac{2+7\frac yx}{4-\frac yx}\] let \[\qquad v=\frac yx\qquad y=vx\qquad \frac {\text dy}{\text dx}=v+x\frac{\text dv}{\text dx}\] \[v+x\frac{\text dv}{\text dx}=\frac{2+7v}{4-v}\]
which is variables separable ,
thank you very very much !!!!
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